What is the tangent of f(x)=3x^4,\at x=-1 ?

The tangent of f(x)=3x^4,\at x=-1 is y=-12x-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3x^4,\at x=-1

tangent of

f (x) = 3 x^{4}, at x = - 1

y = - 12 x - 9

Solution steps

Find the tangent point:

(- 1, 3)

Find the slope of

f (x) = 3 x^{4} : \frac{df ( x )}{d x} = 12 x^{3}

Compute the slope of

f (x) = 3 x^{4}

x = - 1 : m = - 12

Find the line with slope m=

- 12

and passing through

(- 1, 3) : y = - 12 x - 9

y = - 12 x - 9

\int \frac{1}{42} x d x

\frac{d}{d x} (5 x - 8)

f (x) = x^{4} - 8 x^{3} + 4, at x = - 1

n = 0 \sum \infty \frac{8 n}{6 n + 1}

x y^{^{''}} + 2 y^{^{'}} = 12 x^{2}, y^{^{'}} (1) = 4, y (1) = 0

What is the tangent of f(x)=3x^4,\at x=-1 ?
The tangent of f(x)=3x^4,\at x=-1 is y=-12x-9