What is the first derivative of 5x-8 ?

The first derivative of 5x-8 is 5

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derivative of 5x-8

\frac{d}{d x} (5 x - 8)

5

Solution steps

\frac{d}{d x} (5 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x) - \frac{d}{d x} (8)

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (8) = 0

= 5 - 0

Simplify

= 5

f (x) = x^{4} - 8 x^{3} + 4, at x = - 1

n = 0 \sum \infty \frac{8 n}{6 n + 1}

x y^{^{''}} + 2 y^{^{'}} = 12 x^{2}, y^{^{'}} (1) = 4, y (1) = 0

(x^{2} + \frac{2 y}{x}) d x = (3 - ln (x^{2})) d y

\int 1 + 3 x d x