What is the integral of 1+3sqrt(x) ?

The integral of 1+3sqrt(x) is x+2x^{3/2}+C

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integral of 1+3sqrt(x)

\int 1 + 3 x d x

x + 2 x^{\frac{3}{2}} + C

Solution steps

\int 1 + 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x + \int 3 x d x

\int 1 d x = x

\int 3 x d x = 2 x^{\frac{3}{2}}

= x + 2 x^{\frac{3}{2}}

Add a constant to the solution

= x + 2 x^{\frac{3}{2}} + C

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