What is the integral of 28x^3-18x^2+10x ?

The integral of 28x^3-18x^2+10x is 7x^4-6x^3+5x^2+C

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integral of 28x^3-18x^2+10x

\int 28 x^{3} - 18 x^{2} + 10 x d x

7 x^{4} - 6 x^{3} + 5 x^{2} + C

Solution steps

\int 28 x^{3} - 18 x^{2} + 10 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 28 x^{3} d x - \int 18 x^{2} d x + \int 10 x d x

\int 28 x^{3} d x = 7 x^{4}

\int 18 x^{2} d x = 6 x^{3}

\int 10 x d x = 5 x^{2}

= 7 x^{4} - 6 x^{3} + 5 x^{2}

Add a constant to the solution

= 7 x^{4} - 6 x^{3} + 5 x^{2} + C

\frac{d}{d x} (\frac{1}{x ^{\frac{2}{3}}})

x \to 1 lim (arcsin (x))

\frac{d}{d x} (\frac{4 x ^{2} - 5 x + 1}{3 x + 7})

\int_{1}^{4} (5 x^{2} + x) d x

csc (y) + sec^{2} (x) (\frac{d y}{d x}) = 0

What is the integral of 28x^3-18x^2+10x ?
The integral of 28x^3-18x^2+10x is 7x^4-6x^3+5x^2+C