What is the limit as x approaches 1 of arcsin(x) ?

The limit as x approaches 1 of arcsin(x) is pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of arcsin(x)

x \to 1 lim (arcsin (x))

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

x \to 1 lim (arcsin (x))

Plug in the value

x = 1

= arcsin (1)

Use the following trivial identity:

arcsin (1) = \frac{π}{2}

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{2}

\frac{d}{d x} (\frac{4 x ^{2} - 5 x + 1}{3 x + 7})

\int_{1}^{4} (5 x^{2} + x) d x

csc (y) + sec^{2} (x) (\frac{d y}{d x}) = 0

n = 1 \sum \infty \frac{3}{n ( n + 1 )}

f (x) = x, g (x) = x, x = 0, 2

What is the limit as x approaches 1 of arcsin(x) ?
The limit as x approaches 1 of arcsin(x) is pi/2