What is area f(x)=x,g(x)=sqrt(x),x=0,2 ?

The answer to area f(x)=x,g(x)=sqrt(x),x=0,2 is (7-4sqrt(2))/3

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area f(x)=x,g(x)=sqrt(x),x=0,2

area

f (x) = x, g (x) = x, x = 0, 2

\frac{7 - 4 2}{3}

Decimal Notation

0.44771 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x - x d x

Solve

\int_{0}^{2} x - x d x : \frac{7 - 4 2}{3}

The area is:

= \frac{7 - 4 2}{3}

x y^{^{'}} = 8 y - 9 x, y (1) = 0, y (1) = 0

\int \frac{x}{e ^{6 x}} d x

3 x, \frac{3 x}{4}

\frac{d}{d x} ((2 x^{5} - 5 x^{3} + 7 x)^{4})

\int_{1}^{4} x^{2} + 2 x - 5 d x

What is area f(x)=x,g(x)=sqrt(x),x=0,2 ?
The answer to area f(x)=x,g(x)=sqrt(x),x=0,2 is (7-4sqrt(2))/3