What is the solution for xy^'=8y-9x,y(1)=0,y(1)=0 ?

The solution for xy^'=8y-9x,y(1)=0,y(1)=0 is y=(9x)/7-(9x^8)/7

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xy^'=8y-9x,y(1)=0,y(1)=0

x y^{^{'}} = 8 y - 9 x, y (1) = 0, y (1) = 0

y = \frac{9 x}{7} - \frac{9 x ^{8}}{7}

Solution steps

x y^{'} (x) = 8 y - 9 x

Solve linear ODE:

y = \frac{9 x}{7} - \frac{9 x ^{8}}{7}

y = \frac{9 x}{7} - \frac{9 x ^{8}}{7}

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What is the solution for xy^'=8y-9x,y(1)=0,y(1)=0 ?
The solution for xy^'=8y-9x,y(1)=0,y(1)=0 is y=(9x)/7-(9x^8)/7