What is the derivative of f(x)=-(42)/((x+4)^4) ?

The derivative of f(x)=-(42)/((x+4)^4) is (168)/((x+4)^5)

What is the first derivative of f(x)=-(42)/((x+4)^4) ?

The first derivative of f(x)=-(42)/((x+4)^4) is (168)/((x+4)^5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = - \frac{42}{( x + 4 ) ^{4}}

\frac{168}{( x + 4 ) ^{5}}

Solution steps

\frac{d}{d x} (- \frac{42}{( x + 4 ) ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 42 \frac{d}{d x} (\frac{1}{( x + 4 ) ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 42 \frac{d}{d x} ((x + 4)^{- 4})

Apply the chain rule:

- \frac{4}{( x + 4 ) ^{5}} \frac{d}{d x} (x + 4)

= - \frac{4}{( x + 4 ) ^{5}} \frac{d}{d x} (x + 4)

\frac{d}{d x} (x + 4) = 1

= - 42 (- \frac{4}{( x + 4 ) ^{5}} \cdot 1)

Simplify

- 42 (- \frac{4}{( x + 4 ) ^{5}} \cdot 1) : \frac{168}{( x + 4 ) ^{5}}

= \frac{168}{( x + 4 ) ^{5}}

\int_{0}^{5} \frac{1}{x ^{\frac{20}{19}}} d x

\frac{d}{d x} (\frac{x ^{2}}{x ^{3} + 4})

\frac{\partial}{\partial x} (5 y - x + y^{2} sin (y))

\frac{d y}{d x} = y^{3} x e^{x^{2}}

y^{^{''}} - 8 y = 0

What is the derivative of f(x)=-(42)/((x+4)^4) ?
The derivative of f(x)=-(42)/((x+4)^4) is (168)/((x+4)^5)
What is the first derivative of f(x)=-(42)/((x+4)^4) ?
The first derivative of f(x)=-(42)/((x+4)^4) is (168)/((x+4)^5)