What is the integral from 0 to 5 of 1/(x^{20/19)} ?

The integral from 0 to 5 of 1/(x^{20/19)} is diverges

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integral from 0 to 5 of 1/(x^{20/19)}

\int_{0}^{5} \frac{1}{x ^{\frac{20}{19}}} d x

diverges

Solution steps

\int_{0}^{5} \frac{1}{x ^{\frac{20}{19}}} d x

Apply the Power Rule

: [- \frac{19}{x ^{\frac{1}{19}}}]_{0}^{5}

= [- \frac{19}{x ^{\frac{1}{19}}}]_{0}^{5}

Compute the boundaries:

diverges

= diverges

\frac{d}{d x} (\frac{x ^{2}}{x ^{3} + 4})

\frac{\partial}{\partial x} (5 y - x + y^{2} sin (y))

\frac{d y}{d x} = y^{3} x e^{x^{2}}

y^{^{''}} - 8 y = 0

e^{x + y}

What is the integral from 0 to 5 of 1/(x^{20/19)} ?
The integral from 0 to 5 of 1/(x^{20/19)} is diverges