What is the derivative of e^{x+y} ?

The derivative of e^{x+y} is e^{x+y}

What is the first derivative of e^{x+y} ?

The first derivative of e^{x+y} is e^{x+y}

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derivative of

e^{x + y}

e^{x + y}

Solution steps

\frac{d}{d x} (e^{x + y})

Treat

y

as a constant

Apply the chain rule:

e^{x + y} \frac{d}{d x} (x + y)

= e^{x + y} \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1

= e^{x + y} \cdot 1

Simplify

= e^{x + y}

\int_{1}^{4} 5 x + 3 x^{2} - 8 d x

\frac{d y}{d x} = - \frac{( 2 y ^{2} )}{x ^{2}}

a x^{^{''}} + b x = 0

\frac{d}{d x} (e^{t a n h (2 x)})

y^{^{'}} - e^{2 x + y} = 0

What is the derivative of e^{x+y} ?
The derivative of e^{x+y} is e^{x+y}
What is the first derivative of e^{x+y} ?
The first derivative of e^{x+y} is e^{x+y}