What is the derivative of f(x)=x^2-4 ?

The derivative of f(x)=x^2-4 is 2x

What is the first derivative of f(x)=x^2-4 ?

The first derivative of f(x)=x^2-4 is 2x

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derivative of

f (x) = x^{2} - 4

2 x

Solution steps

\frac{d}{d x} (x^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4) = 0

= 2 x - 0

Simplify

= 2 x

\int \frac{1}{x ^{2} ( x + 1 ) ^{2}} d x

x - 2

7 x - 4 x

y^{^{'}} - y^{\frac{5}{3}} = 0

\int \frac{x}{x - 20} d x

What is the derivative of f(x)=x^2-4 ?
The derivative of f(x)=x^2-4 is 2x
What is the first derivative of f(x)=x^2-4 ?
The first derivative of f(x)=x^2-4 is 2x