What is the integral of 2\sqrt[3]{x} ?

The integral of 2\sqrt[3]{x} is 3/2 x^{4/3}+C

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integral of 2\sqrt[3]{x}

\frac{3}{2} x^{\frac{4}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= 2 \cdot \frac{3}{4} x^{\frac{4}{3}}

Simplify

2 \cdot \frac{3}{4} x^{\frac{4}{3}} : \frac{3}{2} x^{\frac{4}{3}}

= \frac{3}{2} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{2} x^{\frac{4}{3}} + C

\int sin^{3} (2 x) cot (2 x) d x

\frac{\partial}{\partial y} (y^{2} + x)

\frac{1}{s} - \frac{s}{s ^{2} + 1}

\int \frac{1}{2 3 - x x + 1} d x

\frac{d}{d x} (ln (x^{2} e^{x}))

What is the integral of 2\sqrt[3]{x} ?
The integral of 2\sqrt[3]{x} is 3/2 x^{4/3}+C