What is the derivative of (1+x^2)/((1-x^2)^2) ?

The derivative of (1+x^2)/((1-x^2)^2) is (2x(x^2+3))/((1-x^2)^3)

What is the first derivative of (1+x^2)/((1-x^2)^2) ?

The first derivative of (1+x^2)/((1-x^2)^2) is (2x(x^2+3))/((1-x^2)^3)

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derivative of

\frac{1 + x ^{2}}{( 1 - x ^{2} ) ^{2}}

\frac{2 x ( x ^{2} + 3 )}{( 1 - x ^{2} ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1 + x ^{2}}{( 1 - x ^{2} ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 + x ^{2} ) ( 1 - x ^{2} ) ^{2} - \frac{d}{d x} ( ( 1 - x ^{2} ) ^{2} ) ( 1 + x ^{2} )}{( ( 1 - x ^{2} ) ^{2} ) ^{2}}

\frac{d}{d x} (1 + x^{2}) = 2 x

\frac{d}{d x} ((1 - x^{2})^{2}) = - 4 x (1 - x^{2})

= \frac{2 x ( 1 - x ^{2} ) ^{2} - ( - 4 x ( 1 - x ^{2} ) ) ( 1 + x ^{2} )}{( ( 1 - x ^{2} ) ^{2} ) ^{2}}

Simplify

\frac{2 x ( 1 - x ^{2} ) ^{2} - ( - 4 x ( 1 - x ^{2} ) ) ( 1 + x ^{2} )}{( ( 1 - x ^{2} ) ^{2} ) ^{2}} : \frac{2 x ( x ^{2} + 3 )}{( 1 - x ^{2} ) ^{3}}

= \frac{2 x ( x ^{2} + 3 )}{( 1 - x ^{2} ) ^{3}}

\frac{d}{d x} (ln (4 - x))

\frac{d}{d x} (\frac{2 - x}{x + 4})

f (t) = 5 t - 8 t^{2}

\frac{\partial}{\partial y} (- x y^{2} z + 4 x y)

\frac{\partial}{\partial x} (sin (x + y) + (x + y))

What is the derivative of (1+x^2)/((1-x^2)^2) ?
The derivative of (1+x^2)/((1-x^2)^2) is (2x(x^2+3))/((1-x^2)^3)
What is the first derivative of (1+x^2)/((1-x^2)^2) ?
The first derivative of (1+x^2)/((1-x^2)^2) is (2x(x^2+3))/((1-x^2)^3)