What is laplacetransform t^2e^{-2t} ?

The answer to laplacetransform t^2e^{-2t} is 2/((s+2)^3)

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laplacetransform t^2e^{-2t}

laplace transform

t^{2} e^{- 2 t}

\frac{2}{( s + 2 ) ^{3}}

Solution steps

L {e^{- 2 t} t^{2}}

Use Laplace Transform table:

L {t^{k} f (t)} = (- 1)^{k} \frac{d ^{k}}{d s ^{k}} (L {f (t)})

For

t^{2} e^{- 2 t} : f (t) = e^{- 2 t}, k = 2

= (- 1)^{2} \frac{d ^{2}}{d s ^{2}} (L {e^{- 2 t}})

L {e^{- 2 t}} : \frac{1}{s + 2}

\frac{d ^{2}}{d s ^{2}} (\frac{1}{s + 2}) = \frac{2}{( s + 2 ) ^{3}}

= (- 1)^{2} \frac{2}{( s + 2 ) ^{3}}

= \frac{2}{( s + 2 ) ^{3}}

x \to 0 lim (e^{0} cos (4) (0))

x \to 3 lim (4 e^{x - 3})

t \to 0 lim (e^{2 t})

\frac{d}{d x} (x^{2} - sin^{2} (x))

y^{^{'}} = e^{2 x} (1 + y^{2})

What is laplacetransform t^2e^{-2t} ?
The answer to laplacetransform t^2e^{-2t} is 2/((s+2)^3)