What is the integral of (1/(sin^2(x))) ?

The integral of (1/(sin^2(x))) is -cot(x)+C

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integral of (1/(sin^2(x)))

\int (\frac{1}{sin ^{2} ( x )}) d x

- cot (x) + C

Solution steps

\int \frac{1}{sin ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{sin ^{2} ( x )} d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

\int \frac{5 x ^{2}}{( x - 1 ) ( x ^{2} + 9 )} d x

x \to 3 lim (x^{2} - 5 x)

\frac{d}{d s} (s^{2} y (s) - 1)

f (x) = x^{2} - 2 x + 1

\frac{d}{d x} (e^{- 0.4 x})

What is the integral of (1/(sin^2(x))) ?
The integral of (1/(sin^2(x))) is -cot(x)+C