What is the derivative of f(x)=4x^2-x ?

The derivative of f(x)=4x^2-x is 8x-1

What is the first derivative of f(x)=4x^2-x ?

The first derivative of f(x)=4x^2-x is 8x-1

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derivative of

f (x) = 4 x^{2} - x

8 x - 1

Solution steps

\frac{d}{d x} (4 x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d x}{d x} = 1

= 8 x - 1

\int \frac{1}{9 x} d x

\int \frac{x ^{2}}{x ^{2} - 4 x + 20} d x

7 e^{x}, 7 x e^{x^{2}}, 1, 7 e

f (x) = \frac{x}{( 1 + x ^{2} )}, at x = 2

\frac{d}{d x} (\frac{3}{x ^{6}} - \frac{1}{x ^{4}} + 5)

What is the derivative of f(x)=4x^2-x ?
The derivative of f(x)=4x^2-x is 8x-1
What is the first derivative of f(x)=4x^2-x ?
The first derivative of f(x)=4x^2-x is 8x-1