What is the tangent of f(x)=x^2+6,\at x=-7 ?

The tangent of f(x)=x^2+6,\at x=-7 is y=-14x-43

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tangent of f(x)=x^2+6,\at x=-7

tangent of

f (x) = x^{2} + 6, at x = - 7

y = - 14 x - 43

Solution steps

Find the tangent point:

(- 7, 55)

Find the slope of

f (x) = x^{2} + 6 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} + 6

x = - 7 : m = - 14

Find the line with slope m=

- 14

and passing through

(- 7, 55) : y = - 14 x - 43

y = - 14 x - 43

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x \to 5 + lim (\frac{x + 2}{5 - x})

\int 2 x \cdot sin (x) \cdot e^{x} d x

\int \frac{1}{x 5 + x ^{2}} d x

What is the tangent of f(x)=x^2+6,\at x=-7 ?
The tangent of f(x)=x^2+6,\at x=-7 is y=-14x-43