derivative f(x)=139+(36)/x+(x^2)/(16)

Lösung

ableitung von

f (x) = 139 + \frac{36}{x} + \frac{x ^{2}}{16}

\frac{x}{8} - \frac{36}{x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (139 + \frac{36}{x} + \frac{x ^{2}}{16})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (139) + \frac{d}{d x} (\frac{36}{x}) + \frac{d}{d x} (\frac{x ^{2}}{16})

\frac{d}{d x} (139) = 0

\frac{d}{d x} (\frac{36}{x}) = - \frac{36}{x ^{2}}

\frac{d}{d x} (\frac{x ^{2}}{16}) = \frac{x}{8}

= 0 - \frac{36}{x ^{2}} + \frac{x}{8}

Vereinfache

= \frac{x}{8} - \frac{36}{x ^{2}}

x^{^{''}} - 6 x^{^{'}} + 25 x = 64 e^{- t}

\frac{d}{d x} (- 7 x^{3})

\frac{\partial}{\partial y} (ln (x^{2} + 1) + y^{2})

d er i v a t i v e arctan (0)

x \to 1 lim (e^{x^{3} - x})