What is the integral from 1 to 27 of \sqrt[3]{x}-1/x ?

The integral from 1 to 27 of \sqrt[3]{x}-1/x is 60-3ln(3)

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integral from 1 to 27 of \sqrt[3]{x}-1/x

60 - 3 ln (3)

Decimal Notation

56.70416 \dots

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{1}^{27} \frac{1}{x} d x = 3 ln (3)

= 60 - 3 ln (3)

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y = \frac{6 x}{x ^{2} + 1}, (0, 0)

\int_{0}^{4} (3 x - \frac{x ^{3}}{4}) d x

\int_{0}^{πa} x^{2} sin^{2} (x) d x

\frac{d}{d x} (\frac{9 x ^{\frac{5}{2}} - 2}{x})

What is the integral from 1 to 27 of \sqrt[3]{x}-1/x ?
The integral from 1 to 27 of \sqrt[3]{x}-1/x is 60-3ln(3)