What is the derivative of (1+i^x) ?

The derivative of (1+i^x) is (1+i)^xln(1+i)

What is the first derivative of (1+i^x) ?

The first derivative of (1+i^x) is (1+i)^xln(1+i)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((1 + i)^{x})

(1 + i)^{x} ln (1 + i)

Solution steps

\frac{d}{d x} ((1 + i)^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= (1 + i)^{x} ln (1 + i)

\frac{\partial}{\partial x} ((4 x + 8) ln (6 x y))

\frac{d}{d x} (4 e^{- 3 x})

\frac{d}{d x} (- cos (2 x) - 2 sin (2 x) (1 - x))

x \frac{d y}{d x} + 2 y = x^{2}

x \to 0 lim (\frac{x}{sin ^{2} ( x )})

What is the derivative of (1+i^x) ?
The derivative of (1+i^x) is (1+i)^xln(1+i)
What is the first derivative of (1+i^x) ?
The first derivative of (1+i^x) is (1+i)^xln(1+i)