What is (\partial)/(\partial y)(-3y) ?

The answer to (\partial)/(\partial y)(-3y) is -3

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(\partial)/(\partial y)(-3y)

\frac{\partial}{\partial y} (- 3 y)

- 3

Solution steps

\frac{\partial}{\partial y} (- 3 y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= - 3 \cdot 1

Simplify

= - 3

y^{^{'}} + \frac{t}{t ^{2} - 16} y = \frac{e ^{t}}{t - 9}

n = 0 \sum \infty cos (nπ)

x = 2 - y^{2}, x = - y

\int_{0}^{\infty} \frac{8}{x ^{2} + 4} d x

\frac{d}{d x} (x \cdot x^{2} + 1)

What is (\partial)/(\partial y)(-3y) ?
The answer to (\partial)/(\partial y)(-3y) is -3