What is the sum from n=0 to infinity of cos(npi) ?

The sum from n=0 to infinity of cos(npi) is diverges

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sum from n=0 to infinity of cos(npi)

n = 0 \sum \infty cos (nπ)

diverges

Solution steps

n = 0 \sum \infty cos (nπ)

Apply Series Divergence Test:

diverges

= diverges

x = 2 - y^{2}, x = - y

\int_{0}^{\infty} \frac{8}{x ^{2} + 4} d x

\frac{d}{d x} (x \cdot x^{2} + 1)

y = x x, (1, 1)

\frac{d}{d x} (\frac{x}{sin ( x )})

What is the sum from n=0 to infinity of cos(npi) ?
The sum from n=0 to infinity of cos(npi) is diverges