What is the derivative of-4e^{-4x} ?

The derivative of-4e^{-4x} is 16e^{-4x}

What is the first derivative of-4e^{-4x} ?

The first derivative of-4e^{-4x} is 16e^{-4x}

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\frac{d}{d x} (- 4 e^{- 4 x})

16 e^{- 4 x}

Solution steps

\frac{d}{d x} (- 4 e^{- 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (e^{- 4 x})

Apply the chain rule:

e^{- 4 x} \frac{d}{d x} (- 4 x)

= e^{- 4 x} \frac{d}{d x} (- 4 x)

\frac{d}{d x} (- 4 x) = - 4

= - 4 e^{- 4 x} (- 4)

Simplify

= 16 e^{- 4 x}

\frac{d}{d x} (7 x - 8)

n = 0 \sum \infty (400) (0.1)^{n}

\frac{d y}{d x} = \frac{x ^{2} + 2}{3 y ^{2}}

(x^{2} + x)^{^{'}}

\frac{d}{d x} (\frac{( x ^{2} )}{sin ( x )})

What is the derivative of-4e^{-4x} ?
The derivative of-4e^{-4x} is 16e^{-4x}
What is the first derivative of-4e^{-4x} ?
The first derivative of-4e^{-4x} is 16e^{-4x}