What is the derivative of sqrt(7x-8) ?

The derivative of sqrt(7x-8) is 7/(2sqrt(7x-8))

What is the first derivative of sqrt(7x-8) ?

The first derivative of sqrt(7x-8) is 7/(2sqrt(7x-8))

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\frac{d}{d x} (7 x - 8)

\frac{7}{2 7 x - 8}

Solution steps

\frac{d}{d x} (7 x - 8)

Apply the chain rule:

\frac{1}{2 7 x - 8} \frac{d}{d x} (7 x - 8)

= \frac{1}{2 7 x - 8} \frac{d}{d x} (7 x - 8)

\frac{d}{d x} (7 x - 8) = 7

= \frac{1}{2 7 x - 8} \cdot 7

Simplify

\frac{1}{2 7 x - 8} \cdot 7 : \frac{7}{2 7 x - 8}

= \frac{7}{2 7 x - 8}

n = 0 \sum \infty (400) (0.1)^{n}

\frac{d y}{d x} = \frac{x ^{2} + 2}{3 y ^{2}}

(x^{2} + x)^{^{'}}

\frac{d}{d x} (\frac{( x ^{2} )}{sin ( x )})

y^{^{'}} - e^{6 x + y} = 0

What is the derivative of sqrt(7x-8) ?
The derivative of sqrt(7x-8) is 7/(2sqrt(7x-8))
What is the first derivative of sqrt(7x-8) ?
The first derivative of sqrt(7x-8) is 7/(2sqrt(7x-8))