What is the derivative of 4x^3-x^2-4x+3 ?

The derivative of 4x^3-x^2-4x+3 is 12x^2-2x-4

What is the first derivative of 4x^3-x^2-4x+3 ?

The first derivative of 4x^3-x^2-4x+3 is 12x^2-2x-4

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\frac{d}{d x} (4 x^{3} - x^{2} - 4 x + 3)

12 x^{2} - 2 x - 4

Solution steps

\frac{d}{d x} (4 x^{3} - x^{2} - 4 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (3)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 12 x^{2} - 2 x - 4 + 0

Simplify

= 12 x^{2} - 2 x - 4

\frac{d}{d x} (y (θ, x) tan (θ))

y \frac{d y}{d x} - y^{3} = y^{2} ln (x)

\frac{d}{d x} ((x - 2)^{2} + 2)

y^{^{'}} + 5 y = e^{- 3 t}

\frac{s + 2}{( s - 1 ) ( s + 3 ) ^{2}}

What is the derivative of 4x^3-x^2-4x+3 ?
The derivative of 4x^3-x^2-4x+3 is 12x^2-2x-4
What is the first derivative of 4x^3-x^2-4x+3 ?
The first derivative of 4x^3-x^2-4x+3 is 12x^2-2x-4