What is the derivative of (x^3-4x)(5x^2+2x) ?

The derivative of (x^3-4x)(5x^2+2x) is 25x^4+8x^3-60x^2-16x

What is the first derivative of (x^3-4x)(5x^2+2x) ?

The first derivative of (x^3-4x)(5x^2+2x) is 25x^4+8x^3-60x^2-16x

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derivative of

(x^{3} - 4 x) (5 x^{2} + 2 x)

25 x^{4} + 8 x^{3} - 60 x^{2} - 16 x

Solution steps

\frac{d}{d x} ((x^{3} - 4 x) (5 x^{2} + 2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3} - 4 x, g = 5 x^{2} + 2 x

= \frac{d}{d x} (x^{3} - 4 x) (5 x^{2} + 2 x) + \frac{d}{d x} (5 x^{2} + 2 x) (x^{3} - 4 x)

\frac{d}{d x} (x^{3} - 4 x) = 3 x^{2} - 4

\frac{d}{d x} (5 x^{2} + 2 x) = 10 x + 2

= (3 x^{2} - 4) (5 x^{2} + 2 x) + (10 x + 2) (x^{3} - 4 x)

Simplify

(3 x^{2} - 4) (5 x^{2} + 2 x) + (10 x + 2) (x^{3} - 4 x) : 25 x^{4} + 8 x^{3} - 60 x^{2} - 16 x

= 25 x^{4} + 8 x^{3} - 60 x^{2} - 16 x

\frac{d}{d x} (e^{x^{4} + 7 x})

\frac{\partial}{\partial x} (7 + x ln (x y - 9))

\frac{d}{d x} ((x^{3} + 5 x^{2} - x^{- 2} + 8)^{- \frac{7}{6}})

q \to 0 + lim (4 q)

\int 22 x^{21} d x

What is the derivative of (x^3-4x)(5x^2+2x) ?
The derivative of (x^3-4x)(5x^2+2x) is 25x^4+8x^3-60x^2-16x
What is the first derivative of (x^3-4x)(5x^2+2x) ?
The first derivative of (x^3-4x)(5x^2+2x) is 25x^4+8x^3-60x^2-16x