What is the derivative of 6x^5(x^4-8) ?

The derivative of 6x^5(x^4-8) is 6(9x^8-40x^4)

What is the first derivative of 6x^5(x^4-8) ?

The first derivative of 6x^5(x^4-8) is 6(9x^8-40x^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

6 x^{5} (x^{4} - 8)

6 (9 x^{8} - 40 x^{4})

Solution steps

\frac{d}{d x} (6 x^{5} (x^{4} - 8))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (x^{5} (x^{4} - 8))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{5}, g = x^{4} - 8

= 6 (\frac{d}{d x} (x^{5}) (x^{4} - 8) + \frac{d}{d x} (x^{4} - 8) x^{5})

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (x^{4} - 8) = 4 x^{3}

= 6 (5 x^{4} (x^{4} - 8) + 4 x^{3} x^{5})

Simplify

6 (5 x^{4} (x^{4} - 8) + 4 x^{3} x^{5}) : 6 (9 x^{8} - 40 x^{4})

= 6 (9 x^{8} - 40 x^{4})

\frac{( 2 s + 13 )}{s ^{2} + 4 s + 13}

\int_{0}^{4} 1

\frac{d}{d x} (7 x^{- 1})

\int 2 x sin (3 x y) d x

x \to - 4 lim (x^{3} + x^{2})

What is the derivative of 6x^5(x^4-8) ?
The derivative of 6x^5(x^4-8) is 6(9x^8-40x^4)
What is the first derivative of 6x^5(x^4-8) ?
The first derivative of 6x^5(x^4-8) is 6(9x^8-40x^4)