What is (\partial)/(\partial y)(x+2y+z) ?

The answer to (\partial)/(\partial y)(x+2y+z) is 2

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(\partial)/(\partial y)(x+2y+z)

\frac{\partial}{\partial y} (x + 2 y + z)

2

Solution steps

\frac{\partial}{\partial y} (x + 2 y + z)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (2 y) + \frac{\partial}{\partial y} (z)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (2 y) = 2

\frac{\partial}{\partial y} (z) = 0

= 0 + 2 + 0

Simplify

= 2

\int x^{2} e^{- 1} d x

\int \frac{( x ^{2} - 4 x + 9 )}{x ^{2} - 6 x + 9} d x

(2 x + 3 y) d x + (3 x + 2) d y = 0

\frac{( 3 s + 7 )}{s ^{2} + 2 s + 4}

f (x) = - 3 x^{2}

What is (\partial)/(\partial y)(x+2y+z) ?
The answer to (\partial)/(\partial y)(x+2y+z) is 2