What is the solution for (2x+3y)dx+(3x+2)dy=0 ?

The solution for (2x+3y)dx+(3x+2)dy=0 is y=-(x^2)/(3x+2)+(c_{1})/(3x+2)

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(2x+3y)dx+(3x+2)dy=0

(2 x + 3 y) d x + (3 x + 2) d y = 0

y = - \frac{x ^{2}}{3 x + 2} + \frac{c _{1}}{3 x + 2}

Solution steps

(2 x + 3 y) d x + (3 x + 2) d y = 0

Solve linear ODE:

y = - \frac{x ^{2}}{3 x + 2} + \frac{c _{1}}{3 x + 2}

y = - \frac{x ^{2}}{3 x + 2} + \frac{c _{1}}{3 x + 2}

\frac{( 3 s + 7 )}{s ^{2} + 2 s + 4}

f (x) = - 3 x^{2}

x^{2} + x, at x = 3

\int \frac{1}{x ^{2} + 6 x + 18} d x

\frac{d}{d x} (\frac{7}{2} x^{2} - 5 x + 1)

What is the solution for (2x+3y)dx+(3x+2)dy=0 ?
The solution for (2x+3y)dx+(3x+2)dy=0 is y=-(x^2)/(3x+2)+(c_{1})/(3x+2)