What is the solution for y^{''}-9y^'=1+3e^{2x} ?

The solution for y^{''}-9y^'=1+3e^{2x} is y=c_{1}e^{9x}+c_{2}-x/9-3/14 e^{2x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-9y^'=1+3e^{2x}

y^{^{''}} - 9 y^{^{'}} = 1 + 3 e^{2 x}

y = c_{1} e^{9 x} + c_{2} - \frac{x}{9} - \frac{3}{14} e^{2 x}

Solution steps

y^{''} (x) - 9 y^{'} (x) = 1 + 3 e^{2 x}

Solve linear ODE:

y = c_{1} e^{9 x} + c_{2} - \frac{x}{9} - \frac{3}{14} e^{2 x}

y = c_{1} e^{9 x} + c_{2} - \frac{x}{9} - \frac{3}{14} e^{2 x}

\frac{d y}{d x} = \frac{y}{x + 1}

t \to 0 lim (sin (5 t))

\frac{d}{d x} (- 10 sin (2 x))

\int \frac{x x}{3} d x

\frac{d y}{d x} + 10 y = 12

What is the solution for y^{''}-9y^'=1+3e^{2x} ?
The solution for y^{''}-9y^'=1+3e^{2x} is y=c_{1}e^{9x}+c_{2}-x/9-3/14 e^{2x}