What is the derivative of-10sin(2x) ?

The derivative of-10sin(2x) is -20cos(2x)

What is the first derivative of-10sin(2x) ?

The first derivative of-10sin(2x) is -20cos(2x)

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\frac{d}{d x} (- 10 sin (2 x))

- 20 cos (2 x)

Solution steps

\frac{d}{d x} (- 10 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 10 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 10 cos (2 x) \cdot 2

Simplify

= - 20 cos (2 x)

\int \frac{x x}{3} d x

\frac{d y}{d x} + 10 y = 12

\frac{d}{d x} (\frac{e ^{2 x} + e ^{4 x}}{3})

f (q) = \frac{500}{q ^{2}}

x \to 4 lim (\frac{x + 1}{x - 3})

What is the derivative of-10sin(2x) ?
The derivative of-10sin(2x) is -20cos(2x)
What is the first derivative of-10sin(2x) ?
The first derivative of-10sin(2x) is -20cos(2x)