What is the integral from-2 to 3 of (x^2-12)-(x-6) ?

The integral from-2 to 3 of (x^2-12)-(x-6) is -125/6

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integral from-2 to 3 of (x^2-12)-(x-6)

\int_{- 2}^{3} (x^{2} - 12) - (x - 6) d x

- \frac{125}{6}

Decimal Notation

- 20.83333 \dots

Solution steps

\int_{- 2}^{3} x^{2} - 12 - (x - 6) d x

Simplify

= \int_{- 2}^{3} x^{2} - x - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{3} x^{2} d x - \int_{- 2}^{3} x d x - \int_{- 2}^{3} 6 d x

\int_{- 2}^{3} x^{2} d x = \frac{35}{3}

\int_{- 2}^{3} x d x = \frac{5}{2}

\int_{- 2}^{3} 6 d x = 30

= \frac{35}{3} - \frac{5}{2} - 30

Simplify

\frac{35}{3} - \frac{5}{2} - 30 : - \frac{125}{6}

= - \frac{125}{6}

x \to 1 lim (x - 1)

x \to 1 lim (3 e^{x - 1})

y = \frac{1}{x - 1}

x \to - 1 lim (x ∣ x - 4 ∣)

\frac{d}{d x} ((arcsin (x))^{2})

What is the integral from-2 to 3 of (x^2-12)-(x-6) ?
The integral from-2 to 3 of (x^2-12)-(x-6) is -125/6