What is area y=4-x^2,x=-1,x=2,y=0 ?

The answer to area y=4-x^2,x=-1,x=2,y=0 is 9

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area y=4-x^2,x=-1,x=2,y=0

area

y = 4 - x^{2}, x = - 1, x = 2, y = 0

9

Solution steps

Apply the area formula:

\int_{- 1}^{2} - x^{2} + 4 d x

Solve

\int_{- 1}^{2} - x^{2} + 4 d x : 9

The area is:

= 9

\frac{d}{d x} (4 - x)

y^{^{'}} = 2 x y^{3}

\frac{d}{d t} (cos (t) + 1)

\frac{\partial}{\partial x} (A^{3} (\frac{x}{y})^{2} (1 - x))

\frac{d}{d x} (\frac{x ^{2} - 9}{x - 3})

What is area y=4-x^2,x=-1,x=2,y=0 ?
The answer to area y=4-x^2,x=-1,x=2,y=0 is 9