What is the first derivative of 1+6x ?

The first derivative of 1+6x is 6

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derivative of 1+6x

\frac{d}{d x} (1 + 6 x)

6

Solution steps

\frac{d}{d x} (1 + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (6 x)

\frac{d}{d x} (1) = 0

\frac{d}{d x} (6 x) = 6

= 0 + 6

Simplify

= 6

\frac{d}{d x} (∣ 2 x ∣)

\frac{d}{d x} ((1 + 2 x)^{- \frac{1}{2}})

10 - 3 x

\int (cos (θ) sin (θ)) d θ

y = x^{2}, y = 9 x