What is (\partial)/(\partial r)(2pir^2+2pirh) ?

The answer to (\partial)/(\partial r)(2pir^2+2pirh) is 4pir+2pih

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(\partial)/(\partial r)(2pir^2+2pirh)

\frac{\partial}{\partial r} (2 π r^{2} + 2 π r h)

4 π r + 2 πh

Solution steps

\frac{\partial}{\partial r} (2 π r^{2} + 2 π r h)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial r} (2 π r^{2}) + \frac{\partial}{\partial r} (2 π r h)

\frac{\partial}{\partial r} (2 π r^{2}) = 4 π r

\frac{\partial}{\partial r} (2 π r h) = 2 πh

= 4 π r + 2 πh

\frac{d}{d x} (2 tan^{2} (x))

\frac{d}{d x} (6 sin (x) cos (x))

\int_{0}^{2} \frac{y}{9 - y ^{2}} d y

\int \frac{( 5 x + 3 )}{x ^{3} - 2 x ^{2} - 3 x} d x

y^{^{'}} = x^{2} \cdot y

What is (\partial)/(\partial r)(2pir^2+2pirh) ?
The answer to (\partial)/(\partial r)(2pir^2+2pirh) is 4pir+2pih