What is the integral of sec^2(11x) ?

The integral of sec^2(11x) is 1/11 tan(11x)+C

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integral of sec^2(11x)

\int sec^{2} (11 x) d x

\frac{1}{11} tan (11 x) + C

Solution steps

\int sec^{2} (11 x) d x

Apply u-substitution

: \int sec^{2} (u) \frac{1}{11} d u

= \int sec^{2} (u) \frac{1}{11} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{11} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= \frac{1}{11} tan (u)

Substitute back

u = 11 x

= \frac{1}{11} tan (11 x)

Add a constant to the solution

= \frac{1}{11} tan (11 x) + C

e^{- 9 t}

y = 3 + 6 x + 8 x e^{x}

\frac{d}{d x} (\frac{x ^{2}}{5 ( 1 - x )})

h (x) = 8 x^{2} - 6

x^{0.5}

What is the integral of sec^2(11x) ?
The integral of sec^2(11x) is 1/11 tan(11x)+C