What is the derivative of f(x)=(-2x^2+4)^4 ?

The derivative of f(x)=(-2x^2+4)^4 is -16x(-2x^2+4)^3

What is the first derivative of f(x)=(-2x^2+4)^4 ?

The first derivative of f(x)=(-2x^2+4)^4 is -16x(-2x^2+4)^3

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derivative of

f (x) = (- 2 x^{2} + 4)^{4}

- 16 x (- 2 x^{2} + 4)^{3}

Solution steps

\frac{d}{d x} ((- 2 x^{2} + 4)^{4})

Apply the chain rule:

4 (- 2 x^{2} + 4)^{3} \frac{d}{d x} (- 2 x^{2} + 4)

= 4 (- 2 x^{2} + 4)^{3} \frac{d}{d x} (- 2 x^{2} + 4)

\frac{d}{d x} (- 2 x^{2} + 4) = - 4 x

= 4 (- 2 x^{2} + 4)^{3} (- 4 x)

Simplify

= - 16 x (- 2 x^{2} + 4)^{3}

y = (\frac{( x + 1 )}{( x + 3 ) ^{2}})

\frac{d y}{d t} = e^{t - y}

\int_{0}^{5} e^{x} sin (x) d x

f (x) = 2 x^{2} - x - 3

\int_{0}^{1} 8 e^{- 4 x} d x

What is the derivative of f(x)=(-2x^2+4)^4 ?
The derivative of f(x)=(-2x^2+4)^4 is -16x(-2x^2+4)^3
What is the first derivative of f(x)=(-2x^2+4)^4 ?
The first derivative of f(x)=(-2x^2+4)^4 is -16x(-2x^2+4)^3