What is the integral from 0 to 5 of e^xsin(x) ?

The integral from 0 to 5 of e^xsin(x) is (-e^5cos(5)+e^5sin(5)+1)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 5 of e^xsin(x)

\int_{0}^{5} e^{x} sin (x) d x

\frac{- e ^{5} cos ( 5 ) + e ^{5} sin ( 5 ) + 1}{2}

Decimal Notation

- 91.70809 \dots

Solution steps

\int_{0}^{5} e^{x} sin (x) d x

Compute the indefinite integral:

\int e^{x} sin (x) d x = - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2} + C

Compute the boundaries:

\int_{0}^{5} e^{x} sin (x) d x = \frac{- e ^{5} cos ( 5 ) + e ^{5} sin ( 5 )}{2} - (- \frac{1}{2})

= \frac{- e ^{5} cos ( 5 ) + e ^{5} sin ( 5 )}{2} - (- \frac{1}{2})

Simplify

= \frac{- e ^{5} cos ( 5 ) + e ^{5} sin ( 5 ) + 1}{2}

f (x) = 2 x^{2} - x - 3

\int_{0}^{1} 8 e^{- 4 x} d x

(0.2) (3.5)

x \to 5 lim (x^{2} - 16)

\int - \frac{y}{x} d x

What is the integral from 0 to 5 of e^xsin(x) ?
The integral from 0 to 5 of e^xsin(x) is (-e^5cos(5)+e^5sin(5)+1)/2