What is the integral of sin((npix)/pi) ?

The integral of sin((npix)/pi) is -1/n cos(nx)+C

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integral of sin((npix)/pi)

\int sin (\frac{nπ x}{π}) d x

- \frac{1}{n} cos (n x) + C

Solution steps

\int sin (\frac{nπ x}{π}) d x

Cancel the common factor:

π

= \int sin (n x) d x

Apply u-substitution

: \int \frac{sin ( u )}{n} d u

= \int \frac{sin ( u )}{n} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{n} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{n} (- cos (u))

Substitute back

u = n x

= \frac{1}{n} (- cos (n x))

Simplify

= - \frac{1}{n} cos (n x)

Add a constant to the solution

= - \frac{1}{n} cos (n x) + C

\int_{0}^{1} x^{\frac{2}{3}} d x

\int 5 yz d x

(\frac{x ^{2}}{x - 5})^{^{'}}

x^{7} (x - 10)^{3}

f (x) = 4 x^{3} e^{x} + e^{x} x^{4}

What is the integral of sin((npix)/pi) ?
The integral of sin((npix)/pi) is -1/n cos(nx)+C