What is the integral of (\sqrt[13]{x}+\sqrt[14]{x}) ?

The integral of (\sqrt[13]{x}+\sqrt[14]{x}) is 13/14 x^{14/13}+14/15 x^{15/14}+C

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integral of (\sqrt[13]{x}+\sqrt[14]{x})

\frac{13}{14} x^{\frac{14}{13}} + \frac{14}{15} x^{\frac{15}{14}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{13}{14} x^{\frac{14}{13}} + \frac{14}{15} x^{\frac{15}{14}}

Add a constant to the solution

= \frac{13}{14} x^{\frac{14}{13}} + \frac{14}{15} x^{\frac{15}{14}} + C

\frac{1}{s ^{2} - 6 s + 18}

\frac{\partial}{\partial x} (\frac{1}{x ^{2} + 4 y ^{2}})

\frac{d y}{d x} = 4 x + y

y^{^{'}} = y (7 - y) - \frac{49}{4}

\frac{d}{d x} (3 x^{3} - 5 x)

What is the integral of (\sqrt[13]{x}+\sqrt[14]{x}) ?
The integral of (\sqrt[13]{x}+\sqrt[14]{x}) is 13/14 x^{14/13}+14/15 x^{15/14}+C