What is the integral of ((5x^2+2x-5))/(x^3-x) ?

The integral of ((5x^2+2x-5))/(x^3-x) is 5ln|x|-ln|x+1|+ln|x-1|+C

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integral of ((5x^2+2x-5))/(x^3-x)

\int \frac{( 5 x ^{2} + 2 x - 5 )}{x ^{3} - x} d x

5 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + C

Solution steps

\int \frac{5 x ^{2} + 2 x - 5}{x ^{3} - x} d x

Take the partial fraction of

\frac{5 x ^{2} + 2 x - 5}{x ^{3} - x} : \frac{5}{x} - \frac{1}{x + 1} + \frac{1}{x - 1}

= \int \frac{5}{x} - \frac{1}{x + 1} + \frac{1}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{5}{x} d x - \int \frac{1}{x + 1} d x + \int \frac{1}{x - 1} d x

\int \frac{5}{x} d x = 5 ln ∣ x ∣

\int \frac{1}{x + 1} d x = ln ∣ x + 1 ∣

\int \frac{1}{x - 1} d x = ln ∣ x - 1 ∣

= 5 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣

Add a constant to the solution

= 5 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + C

f (x) = \frac{2 x - 1}{2 x + 1}, (- 1, 3)

\int \frac{z ^{2}}{y} d y

\frac{( s + 1 )}{s ^{2} + s + 10}

\frac{d}{d x} (ln (\frac{x ^{3} + 4}{2 x}))

y^{^{'}} + 2 y = 2 e^{x}

What is the integral of ((5x^2+2x-5))/(x^3-x) ?
The integral of ((5x^2+2x-5))/(x^3-x) is 5ln|x|-ln|x+1|+ln|x-1|+C