What is the first derivative of 3x+1 ?

The first derivative of 3x+1 is 3

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derivative of 3x+1

derivative of

3 x + 1

3

Solution steps

\frac{d}{d x} (3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 3 + 0

Simplify

= 3

(y^{2} + y x) d x - (x^{2}) d y = 0

x \to 2 lim (x^{2} + 8)

x^{7} e^{x} 5

x \to 0 lim (\frac{sin ^{2} ( x )}{x})

y = 1 x^{2}