What is the first derivative of y=1x^2 ?

The first derivative of y=1x^2 is 2x

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derivative of y=1x^2

derivative of

y = 1 x^{2}

2 x

Solution steps

\frac{d}{d x} (1 \cdot x^{2})

Simplify

1 \cdot x^{2} : x^{2}

= \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2 - 1}

Simplify

= 2 x

x \to - 1 lim (e^{x})

2 y^{^{'}} + 3 y = 5

g (t) = \frac{1}{t}

\int (x + 1)^{2} e^{- x} d x

\int 4 x d x