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Popular >

2y^'+3y=5

Solution

2 y^{^{'}} + 3 y = 5

Solution

y = - \frac{e ^{\frac{- 3 t - c _{1}}{2}}}{3} + \frac{5}{3}

Solution steps

2 y^{'} (t) + 3 y = 5

Solve separable ODE:

y = - \frac{e ^{\frac{- 3 t - c _{1}}{2}}}{3} + \frac{5}{3}

y = - \frac{e ^{\frac{- 3 t - c _{1}}{2}}}{3} + \frac{5}{3}

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Frequently Asked Questions (FAQ)

What is the solution for 2y^'+3y=5 ?
The solution for 2y^'+3y=5 is y=-(e^{(-3t-c_{1})/2})/(3)+5/3