What is the derivative of 8csc(x)+2 ?

The derivative of 8csc(x)+2 is -8cot(x)csc(x)

What is the first derivative of 8csc(x)+2 ?

The first derivative of 8csc(x)+2 is -8cot(x)csc(x)

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derivative of

8 csc (x) + 2

- 8 cot (x) csc (x)

Solution steps

\frac{d}{d x} (8 csc (x) + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 csc (x)) + \frac{d}{d x} (2)

\frac{d}{d x} (8 csc (x)) = - 8 cot (x) csc (x)

\frac{d}{d x} (2) = 0

= - 8 cot (x) csc (x) + 0

Simplify

= - 8 cot (x) csc (x)

f (x) = x - 2 sin (x)

n = 0 \sum \infty \frac{1}{2 ^{n} - 1}

\frac{\partial}{\partial x} (z - e^{x y})

ln (\frac{( e ^{x} + 1 )}{e ^{x} - 1})

y^{^{''}} - 6 y^{^{'}} - 7 y = 0, y (2) = - \frac{1}{3}, y^{^{'}} (0) = 0

What is the derivative of 8csc(x)+2 ?
The derivative of 8csc(x)+2 is -8cot(x)csc(x)
What is the first derivative of 8csc(x)+2 ?
The first derivative of 8csc(x)+2 is -8cot(x)csc(x)