What is the solution for (dy)/(dx)=-10x^4+8x^3 ?

The solution for (dy)/(dx)=-10x^4+8x^3 is y=-2x^5+2x^4+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=-10x^4+8x^3

\frac{d y}{d x} = - 10 x^{4} + 8 x^{3}

y = - 2 x^{5} + 2 x^{4} + c_{1}

Solution steps

\frac{d y}{d x} = - 10 x^{4} + 8 x^{3}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = - 10 x^{4} + 8 x^{3}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 10 x^{4} + 8 x^{3} d x

\int - 10 x^{4} + 8 x^{3} d x = - 2 x^{5} + 2 x^{4} + c_{1}

y = - 2 x^{5} + 2 x^{4} + c_{1}

f (x) = 7 x - x, (4, 26)

f (x) = (\frac{x + 11}{x - 11})^{6}

\int x^{3} e^{4 x^{2}} d x

\frac{d}{d x} (\frac{2 sin ( x )}{sec ( x )})

\frac{2}{( s - 4 ) ^{2}}

What is the solution for (dy)/(dx)=-10x^4+8x^3 ?
The solution for (dy)/(dx)=-10x^4+8x^3 is y=-2x^5+2x^4+c_{1}