What is laplacetransform 4sin(4t) ?

The answer to laplacetransform 4sin(4t) is (16)/(s^2+16)

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laplacetransform 4sin(4t)

laplace transform

4 sin (4 t)

\frac{16}{s ^{2} + 16}

Solution steps

L {4 sin (4 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {sin (4 t)}

L {sin (4 t)} : \frac{4}{s ^{2} + 16}

= 4 \cdot \frac{4}{s ^{2} + 16}

Refine

4 \frac{4}{s ^{2} + 16} : \frac{16}{s ^{2} + 16}

= \frac{16}{s ^{2} + 16}

d y = x y d x

x - 5

\int \frac{8}{( x + 2 ) ( x ^{2} + 4 )} d x

\frac{\partial}{\partial x} (cos (x y) + sin (yz))

\frac{d}{d x} (\frac{8 x}{9 - tan ( x )})

What is laplacetransform 4sin(4t) ?
The answer to laplacetransform 4sin(4t) is (16)/(s^2+16)