What is the derivative of-2sin^2(x) ?

The derivative of-2sin^2(x) is -2sin(2x)

What is the first derivative of-2sin^2(x) ?

The first derivative of-2sin^2(x) is -2sin(2x)

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\frac{d}{d x} (- 2 sin^{2} (x))

- 2 sin (2 x)

Solution steps

\frac{d}{d x} (- 2 sin^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (sin^{2} (x))

Apply the chain rule:

2 sin (x) \frac{d}{d x} (sin (x))

= 2 sin (x) \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= - 2 \cdot 2 sin (x) cos (x)

Simplify

- 2 \cdot 2 sin (x) cos (x) : - 2 sin (2 x)

= - 2 sin (2 x)

\frac{d}{d x} (4 x^{2} + x + 1)

n = 1 \sum \infty \frac{( ln ( 3 n ) )}{n}

(2 x^{3} + 3)^{6}

(2 x - 3)^{6}

What is the derivative of-2sin^2(x) ?
The derivative of-2sin^2(x) is -2sin(2x)
What is the first derivative of-2sin^2(x) ?
The first derivative of-2sin^2(x) is -2sin(2x)