What is the f(x)=e^{sqrt(x)}+ln(x+1) ?

The f(x)=e^{sqrt(x)}+ln(x+1) is Domain: x>= 0 Y Intercepts: (0,1) Asymptotes: None

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f(x)=e^{sqrt(x)}+ln(x+1)

f (x) = e^{x} + ln (x + 1)

Domain : x \geq 0

Y Intercepts : (0, 1)

Asymptotes : None

Interval Notation

Domain : [0, \infty)

Solution steps

Domain of

e^{x} + ln (x + 1) : x \geq 0

Axis interception points of

e^{x} + ln (x + 1) :

Y Intercepts

: (0, 1)

Asymptotes of

e^{x} + ln (x + 1) :

None

\frac{1}{2 x ^{\frac{1}{2}}} + \frac{1}{4 x ^{\frac{3}{4}}}

k = 1 \sum \infty k^{- 2.4}

6 x^{2} + \frac{768}{x}

x \to + 1 lim (\frac{- 1}{x - 1})

\frac{d}{d x} (\frac{ln ( x ^{3} + 1 )}{2 ^{x^{4}} - 6})

What is the f(x)=e^{sqrt(x)}+ln(x+1) ?
The f(x)=e^{sqrt(x)}+ln(x+1) is Domain: x>= 0<br/>Y Intercepts: (0,1)<br/>Asymptotes: None