What is the derivative of 1/(2x^{1/2)}+1/(4x^{3/4)} ?

The derivative of 1/(2x^{1/2)}+1/(4x^{3/4)} is -1/(4x^{3/2)}-3/(16x^{7/4)}

What is the first derivative of 1/(2x^{1/2)}+1/(4x^{3/4)} ?

The first derivative of 1/(2x^{1/2)}+1/(4x^{3/4)} is -1/(4x^{3/2)}-3/(16x^{7/4)}

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derivative of

\frac{1}{2 x ^{\frac{1}{2}}} + \frac{1}{4 x ^{\frac{3}{4}}}

- \frac{1}{4 x ^{\frac{3}{2}}} - \frac{3}{16 x ^{\frac{7}{4}}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x ^{\frac{1}{2}}} + \frac{1}{4 x ^{\frac{3}{4}}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{2 x ^{\frac{1}{2}}}) + \frac{d}{d x} (\frac{1}{4 x ^{\frac{3}{4}}})

\frac{d}{d x} (\frac{1}{2 x ^{\frac{1}{2}}}) = - \frac{1}{4 x ^{\frac{3}{2}}}

\frac{d}{d x} (\frac{1}{4 x ^{\frac{3}{4}}}) = - \frac{3}{16 x ^{\frac{7}{4}}}

= - \frac{1}{4 x ^{\frac{3}{2}}} - \frac{3}{16 x ^{\frac{7}{4}}}

k = 1 \sum \infty k^{- 2.4}

6 x^{2} + \frac{768}{x}

x \to + 1 lim (\frac{- 1}{x - 1})

\frac{d}{d x} (\frac{ln ( x ^{3} + 1 )}{2 ^{x^{4}} - 6})

\int (1 - 2 x) e^{- x} d x

What is the derivative of 1/(2x^{1/2)}+1/(4x^{3/4)} ?
The derivative of 1/(2x^{1/2)}+1/(4x^{3/4)} is -1/(4x^{3/2)}-3/(16x^{7/4)}
What is the first derivative of 1/(2x^{1/2)}+1/(4x^{3/4)} ?
The first derivative of 1/(2x^{1/2)}+1/(4x^{3/4)} is -1/(4x^{3/2)}-3/(16x^{7/4)}